Newton-Raphson-Method
Question 1 |
In the Newton-Raphson method, an initial guess of x0 = 2 is made and the sequence x0, x1, x2 … is obtained for the function
0.75x3 – 2x2 – 2x + 4 = 0 Consider the statements (I) x3 = 0. (II) The method converges to a solution in a finite number of iterations.Which of the following is TRUE?
Only I | |
Only II | |
Both I and II | |
Neither I nor II |
Question 1 Explanation:
Note: Numerical methods are not in GATE CS syllabus.
Question 2 |
Newton-Raphson method is used to compute a root of the equation x2 - 13 = 0 with 3.5 as the initial value. The approximation after one iteration is
3.575 | |
3.676 | |
3.667 | |
3.607
|
Question 2 Explanation:
Note: Out of syllabus.
Question 3 |
square of R
| |
reciprocal of R | |
square root of R
| |
logarithm of R
|
Question 3 Explanation:
Note: Out of syllabus.
Question 4 |
Consider the function f(x) = x2 - 2x - 1. Suppose an execution of the Newton-
Raphson method to find a zero of f(x) starts with an approximation x0 = 2 0f x.
What is the value of x2, 'the approximation of x' that the algorithm produces after two iterations, rounded to three decimal places?
2.417 | |
2.419 | |
2.423 | |
2.425 |
Question 4 Explanation:
Note: Out of syllabus.
Question 5 |
1.5
| |
√2
| |
1.6 | |
1.4 |
Question 5 Explanation:
Given series is
xn+1=xn/2+9/8xn ⟶ (I); x0=0.5
Equation based on Newton-Rapson is
xn+1=xn-f(xn)/f'(xn)⟶ (II)
Equate I and II
xn-f(xn)/f'(xn)=xn/2+9/8xn
xn-f(xn)/f'(xn)=xn-xn/2+9/8xn
xn-f(xn)/f'(xn)=xn-(4xn2-9)/8xn
So, f(x)=4xn2-9
4x2-9=0
4x2=9
x2=9/4
x=±3/2
x=±1.5
Equation based on Newton-Rapson is
xn+1=xn-f(xn)/f'(xn)⟶ (II)
Equate I and II
xn-f(xn)/f'(xn)=xn/2+9/8xn
xn-f(xn)/f'(xn)=xn-xn/2+9/8xn
xn-f(xn)/f'(xn)=xn-(4xn2-9)/8xn
So, f(x)=4xn2-9
4x2-9=0
4x2=9
x2=9/4
x=±3/2
x=±1.5
Question 6 |
A piecewise linear function f(x) is plotted using thick solid lines in the figure below
If we use the Newton-Raphson method to find the roots of f(x) = 0 using x0, x1 and x2 respectively as initial guesses, the roots obtained would be

1.3, 0.6, and 0.6 respectively
| |
0.6, 0.6, and 1.3 respectively
| |
1.3, 1.3, and 0.6 respectively
| |
1.3, 0.6, and 1.3 respectively |
Question 6 Explanation:
Note: Out of syllabus.
Question 7 |
X2 = 3 | |
X3 = 3 | |
X2 = 2 | |
X3 = 2 |
Question 7 Explanation:
Newton Rampson formula,


Question 8 |
The Newton-Raphson method is to be used to find the root of the equation f(x)=0 where xo is the initial approximation and f' is the derivative of f. The method converges
always | |
only if f is a polynomial | |
only if f(x0) < 0 | |
None of the above |
Question 8 Explanation:
Note: Out of syllabus.
Question 9 |
The Newton-Raphson method is used to find the root of the equation x2 − 2 = 0. If the iterations are started form –1, the iterations will
converge to -1 | |
converge to √2 | |
converge to - √2 | |
not converge |
Question 9 Explanation:

Question 10 |
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Question 10 Explanation:
Note: Out of syllabus.
Question 11 |
The iteration formula to find the square root of a positive real number b using the Newton Raphson method is
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None of the above |
Question 11 Explanation:
Note: Out of syllabus.
There are 11 questions to complete.